tugas fisika

JAWABAN DARI SOAL NO. 1

DIKET : Q1 = 20 µC = 20 * 10 -6 C
Q2 = 40 µC = 40 * 10 -6 C
r = 6 cm = 6 * 10 -2 m
k = 9 * 10 -9 Nm2/c2

DIT : F12=…..?

JAWAB : F12 = F21

= k Q1 * Q2
R2

= 9 * 10 -9 Nm2/c2 20 * 10 -6 C * 40 * 10 -6 C
(6 * 10 -2 m)2

= 9 * 10 -9 Nm2/c2 800 * 10 -12 C
36 * 10 -4 m2

= 9 * 10 -9 Nm2/c2 * 800 * 10 -12 C
36 * 10 -4 m2

= 2000 N

JAWABAN DARI SOAL NO. 2


DIKET : Q1 = 30 µC = 30 * 10 -6 C
Q2 = 50 µC = 50 * 10 -6 C
F12= 200 N
k = 9 * 10 -9 Nm2/c2

DIT : r2=…..?

JAWAB : F12 = k Q1 * Q2
r2

200 N = 9 * 10 -9 Nm2/c2 30 * 10 -6 C * 50 * 10 -6 C
r2

200 N = 9 * 10 -9 Nm2/c2 1500 * 10 -12 C
r2

200 N = 9 * 10 -9 Nm2/c2 * 1500 * 10 -12 C
r2

200 N = 13500 * 10 -11 C
r2

r2 = 13500 * 10 -11 C
200 N
r2 = 33,75 cm